Thevenin and Norton Equivalent circuits are most often used to simplify a circuit. They are useful when you are interested about the behavior of an element connected to a rather complicated system through terminals a and b (this scenario is addressed in part c of the question).

Read MoreAssume V_s(t) is equal to 3u(t). Find v(t) as a function of time and find the capacitances of the two capacitors. Assume all initial conditions are 0.

Read MoreFirst thing to address is what is D.C. Steady State. Basically, all that means is that the circuit has been active/running for a long time. For power dissipating elements like resistors, this doesn’t mean much, but for energy storing elements such as inductors and capacitors it changes how they behave.

Read MoreA lot of people seem to freak out when they see an *i* in math or *j* in electrical engineering. So hopefully this will help. The first thing we want to go over is what *i* and *j* even are.

Today we’re going to confront a simple lie you learned in high school, and replace it with something more complicated. The topic today is the unit circle. Personally, I don’t see that many uses for the unit circle, aside from teaching students how to deal with trig identities and right triangles. But the unit circle become much more interesting when you use it to describe imaginary numbers.

Read MoreBefore we start the problem, we should go over a couple things about op amps that’ll help us solve the problem and check our work. For one, notice how the resistor for Vo is connected to the negative terminal of the op amp (not directly, as it goes through the 63 k-ohm resistor, but you could draw a line between Vo and the negative terminal without making a new wire). This means that the op amp is undergoing negative feedback (NFB).

Read MoreThe first thing you should notice about this circuit is that there are two different types of sources: a dependent source (the arrow in the diamond), and an independent source (the arrow in the circle). Independent sources are independent of the circuit--so that source will always push 15 A of current into the circuit, regardless of the circuit elements.

Read MoreFind the value of the voltage *v *in the circuit below.

The first thing you should notice is the two different types of sources (current sources are the ones with arrows in the middle of them, voltage sources are the ones with the plus and minus). The 5 ampere current source (the arrow with a circle around it) and the 16 volt voltage source (the circle with a plus and minus in it), are independent sources.

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